What is Zeno's Dichotomy Paradox? - Colm Kelleher

什麼是芝諾的二分法悖論? - Colm Kelleher

3,740,328 views

2013-04-15 ・ TED-Ed


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What is Zeno's Dichotomy Paradox? - Colm Kelleher

什麼是芝諾的二分法悖論? - Colm Kelleher

3,740,328 views ・ 2013-04-15

TED-Ed


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00:00
Translator: Andrea McDonough Reviewer: Bedirhan Cinar
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譯者: Jephian Lin 審譯者: Regina Chu
00:15
This is Zeno of Elea,
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這位是埃利亞的芝諾,
00:16
an ancient Greek philosopher
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一位古希臘哲學家,
00:18
famous for inventing a number of paradoxes,
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因發明許多悖論而聞名。
00:21
arguments that seem logical,
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悖論是指看似有道理,
00:22
but whose conclusion is absurd or contradictory.
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但結論卻是荒謬 或矛盾的論證。
00:25
For more than 2,000 years,
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兩千多年以來,
00:27
Zeno's mind-bending riddles have inspired
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芝諾那些誤導思路的難題 啟發了許多
00:29
mathematicians and philosophers
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數學家與哲學家
00:31
to better understand the nature of infinity.
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來了解「無窮」的本質。
00:33
One of the best known of Zeno's problems
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最有名的一個芝諾難題
00:35
is called the dichotomy paradox,
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叫做二分法悖論,
00:37
which means, "the paradox of cutting in two" in ancient Greek.
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在古希臘文的意思就是「切割為二詭辯」。
00:41
It goes something like this:
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內容大約是這樣:
00:43
After a long day of sitting around, thinking,
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芝諾在漫長地坐著沉思一天後,
00:46
Zeno decides to walk from his house to the park.
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決定從家裡散步到公園。
00:48
The fresh air clears his mind
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清新的空氣啟發他的心靈
00:50
and help him think better.
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並讓他想得更清楚。
00:51
In order to get to the park,
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要走到公園,
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he first has to get half way to the park.
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他必須先走到路程的中點。
00:55
This portion of his journey
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他這部份的旅程
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takes some finite amount of time.
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要花一些有限的時間。
00:58
Once he gets to the halfway point,
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一旦他到達這中點,
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he needs to walk half the remaining distance.
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他必須再走到剩下距離的中點。
01:02
Again, this takes a finite amount of time.
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這又花了一些有限的時間。
01:05
Once he gets there, he still needs to walk
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一旦他到那兒,他還是必須再走到
01:08
half the distance that's left,
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剩下距離的中點,
01:09
which takes another finite amount of time.
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那也會花另一些有限的時間。
01:12
This happens again and again and again.
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這會一次又一次的發生。
01:15
You can see that we can keep going like this forever,
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你可以見到我們 永遠都在這過程打轉,
01:18
dividing whatever distance is left
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就是不斷將剩的距離分成
01:19
into smaller and smaller pieces,
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更小更細的路段,
01:21
each of which takes some finite time to traverse.
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每一段都須要一些 有限的時間才能通過。
01:25
So, how long does it take Zeno to get to the park?
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所以,芝諾要多久才能走到公園?
01:27
Well, to find out, you need to add the times
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嗯,要得到答案,你必須把每段路段
01:30
of each of the pieces of the journey.
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所花的時間加起來。
01:32
The problem is, there are infinitely many of these finite-sized pieces.
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而問題是,有無限個這種 「有限的時間」。
01:36
So, shouldn't the total time be infinity?
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所以,全部的時間也應該要是無限大嗎?
01:39
This argument, by the way, is completely general.
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順帶一提,這個論證是很通用的。
01:42
It says that traveling from any location to any other location
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它說明從任何地點移動到 任何其它地點
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should take an infinite amount of time.
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應該要花無窮的時間。
01:47
In other words, it says that all motion is impossible.
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換句話說,它說明所有運動都是不可能的。
01:51
This conclusion is clearly absurd,
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這個結果顯然很荒謬,
01:52
but where is the flaw in the logic?
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但邏輯上的瑕疵在哪裡?
01:54
To resolve the paradox,
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要解開這個悖論,
01:55
it helps to turn the story into a math problem.
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把故事轉換成數學問題 會有所幫助。
01:58
Let's supposed that Zeno's house is one mile from the park
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我們假設芝諾的家 距離公園有一英里,
02:01
and that Zeno walks at one mile per hour.
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而芝諾每小時走一英里。
02:04
Common sense tells us that the time for the journey
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常理告訴我們這趟旅程
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should be one hour.
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應該要花一小時。
02:08
But, let's look at things from Zeno's point of view
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但是,讓我們從芝諾的觀點來看看
02:10
and divide up the journey into pieces.
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並把路程分程許多小段。
02:13
The first half of the journey takes half an hour,
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最初的一段路程要花 1/2 小時,
02:15
the next part takes quarter of an hour,
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下一段要花 1/4 小時,
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the third part takes an eighth of an hour,
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而第三段要花 1/8 小時,
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and so on.
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02:20
Summing up all these times,
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以此類推。
將這些時間全部加起來,
02:22
we get a series that looks like this.
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我們得到一串 長成這樣的級數。
02:24
"Now", Zeno might say,
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「現在」,芝諾可能會說,
02:25
"since there are infinitely many of terms
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「因為方程式右邊有無限項,
02:27
on the right side of the equation,
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每項又都是有限的,
02:29
and each individual term is finite,
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它們的總和
02:31
the sum should equal infinity, right?"
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應該是無窮,對吧?」
02:34
This is the problem with Zeno's argument.
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這就是芝諾論證的問題了。
02:36
As mathematicians have since realized,
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數學家從此明白,
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it is possible to add up infinitely many finite-sized terms
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把無限個有限的量相加 是有可能得到
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and still get a finite answer.
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一個有限的答案。
02:44
"How?" you ask.
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「怎麼會呢?」你可能會問。
02:45
Well, let's think of it this way.
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嗯,我們可以這樣想。
02:47
Let's start with a square that has area of one meter.
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我們考慮一個 一公尺見方的正方形。
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Now let's chop the square in half,
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現在把這個正方形 分成兩半,
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and then chop the remaining half in half,
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再把剩的分半,
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and so on.
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接著往下做。
02:56
While we're doing this,
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當我們這麼做時,
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let's keep track of the areas of the pieces.
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我們依序記錄每塊的面積。
03:00
The first slice makes two parts,
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最初的切片有兩部份,
03:02
each with an area of one-half
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每部份的面積都是 1/2,
03:04
The next slice divides one of those halves in half,
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而下一次切片把其中一個 1/2 再分成兩半,
03:06
and so on.
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依此類推。
03:07
But, no matter how many times we slice up the boxes,
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但,無論我們切割了幾次,
03:10
the total area is still the sum of the areas of all the pieces.
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整塊面積還是所有小面積的總和。
03:14
Now you can see why we choose this particular way
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現在你可以了解 為什麼要選這麼特別的方式
03:17
of cutting up the square.
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來切割正方形。
03:18
We've obtained the same infinite series
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我們已經做出了那串 相同的無窮級數,
03:20
as we had for the time of Zeno's journey.
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就是在芝諾的旅程中 算出來的那串。
03:23
As we construct more and more blue pieces,
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當我們建構了更多的藍色小方塊,
03:25
to use the math jargon,
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用數學的行話來說,
03:27
as we take the limit as n tends to infinity,
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就是當我們取 n 趨近到無窮時的極限,
03:30
the entire square becomes covered with blue.
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整個正方形都被藍色蓋住了。
03:33
But the area of the square is just one unit,
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但正方形的面積就只有 1 平方單位而已,
03:35
and so the infinite sum must equal one.
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所以無窮項的總合一定是 1。
03:38
Going back to Zeno's journey,
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我們回到芝諾的旅程,
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we can now see how how the paradox is resolved.
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我們可以看到這悖論 是如何被解決的。
03:42
Not only does the infinite series sum to a finite answer,
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不止是無限項加起來可能是有限,
03:45
but that finite answer is the same one
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而且這個有限的答案還是一樣的,
03:47
that common sense tells us is true.
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和常理告訴我們的一樣 ──
03:50
Zeno's journey takes one hour.
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芝諾的旅程要花一小時。
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