Can you solve the private eye riddle? - Henri Picciotto

翻译人员: Yan Li Xiao 校对人员: Yuwei Wu

As Numberland’s best detective, you thought you’d seen it all.

作为 Numberland 最好的侦探， 你以为你已经看过了一切.

But the desiccated corpses of prominent natural numbers—

但是著名自然数的干枯尸体—

whole numbers greater than 0—

大于 0 的整数—

have been showing up all over the city for the past week.

已经在过去一周出现在整个城市。

All of Digitopolis is on lockdown from sundown to sunrise,

从日落到日出所有 Digitopolis 都处于锁定状态，

and it’s still not enough to stop what can only be described

仍然不足以停止可以被描述成

as a vampiric feeding frenzy.

吸血鬼的疯狂进食。

The police are helpless, and have turned to you.

警察很无奈，并转向你。

You put the missing persons case you’ve been investigating on hold

你把你一直在调查的失踪人员案搁置

and study the evidence.

并研究证据。

Here’s what you know:

以下是你所知道的：

most victims have been completely drained of their life’s essence.

大多数受害者已经完全 耗尽了他们生命的精华。

Some have a thin line of slime separating digits—

有些有细线的粘液来分隔数字—

some of which were drained and others spared.

其中一些被排干了其他人幸免于难。

Which leads you to mystery one:

这把你导向一个神秘的：

what’s the significance of the slime-lines,

粘液线有什么意义，

and why are certain digits untouched?

为什么某些数字没有被触及？

Pause here to figure it out yourself. Answer in 3

在这里停下来自己弄清楚。 回答3秒后揭晓

Answer in 2

2秒

Answer in 1

1秒

Let’s start by looking for a pattern in the victims.

让我们从寻找受害者的规律开始。

Why have some been fully drained, and some slimed?

为什么有些已经排干了， 有些有粘液？

Well, the slime-lined are in their prime—

粘液衬里的正处于鼎盛时期—

which is to say they’re prime numbers, divisible only by 1 and themselves.

也就是说，它们是质数， 只能被 1 和自己整除。

Not a single one of the unslimed numbers, on the other hand, is.

没有一个没有粘液的数字， 另一方面，是。

Furthermore, the drained parts of the slimed primes are not, themselves, prime.

此外，黏糊糊的素数的排干部分 本身并不是质数。

When 71 got slimed, 7 was prime, but 1 was not.

当 71 变黏糊时， 7 是质数，但 1 不是。

If 461 had been split into 4 and 61, the right side would have been prime,

如果 461 被分成 4 和 61， 右边本来是质数，

but instead it was split further into non-prime digits.

但它被进一步分裂 变成非质数。

And when 2099 got slimed, the attacker went with 20 and 99,

当 2099 变黏糊时， 攻击者选择了 20 和 99，

and was able to drain both.

并且能够排出两者。

So you have a big problem.

所以你有一个大问题。

There are infinite potential victims:

有无限的潜在受害者：

all non-prime numbers,

所有非质数,

and all prime numbers that can be slime-lined

以及所有可以有粘液的质数

to reveal at least one non-prime number.

来显示至少一个非质数。

In fact, you can only think of a few numbers that aren't vulnerable.

其实你只能想到几个 不易受到攻击的数字。

First of all, the one digit primes: 2, 3, 5, and 7.

首先，一位数质数： 2、3、5 和 7。

Then primes like 23, which could only be split into 2 and 3, both prime.

然后像 23 这样的质数，它只能是 分成 2 和 3，都是质数。

These numbers are familiar, but why?

这些数字很熟悉，但为什么呢？

Aha! Your missing person’s case.

啊哈！ 你的失踪人员案件。

Someone is kidnapping the numbers that can’t be drained:

有人在绑架 无法排干的数字：

we’ll call them the immune.

我们称他们为免疫者。

If you can identify the four immune who remain,

如果你能识别出四种 留下来免疫者，

perhaps you can get to them first and figure out what’s going on.

也许你可以先找到他们 并弄清楚发生了什么。

Who are the immune? Pause here to figure it out yourself.

谁是免疫者？ 在这里停下来自己弄清楚。

Answer in 2

答案 2 秒后揭晓

Answer in 1

答案 1 秒后揭晓

There are 4 one-digit immune: 2, 3, 5, and 7.

有 4 个一位数免疫者： 2、3、5 和 7。

All have already been kidnapped.

所有都已经被绑架了。

But every digit in all of the immune must be one of those four numbers;

但每一个免疫者的数字 必须是这四个数字之一；

otherwise there would be a non-prime split possible.

否则可能会有 非质数的分裂。

That means there are only these 16 candidates among the two-digit numbers.

这意味着两位数中 只有这 16 个候选人。

The ones that are prime must be immune.

那些质数必须是免疫的.

We can eliminate anything that ends in 2 or 5,

我们可以排除 以 2 或 5 结尾的任何东西，

as they’ll always be divisible by 2 and 5.

因为它们总是能被 2 和 5 整除。

This diagonal is also out, as they’re divisible by 11.

这个对角线也可以排除， 因为它们可以被 11 整除。

If the digits of a number add up to a multiple of 3,

如果一个数字里的数字相加 为 3 的倍数，

it’s divisible by 3.

可以被 3 整除。

So that eliminates 57 and 27, leaving these numbers.

这样就消除了 57 和 27， 留下这些数字。

Which, upon double-checking, are, in fact, immune.

经过仔细检查， 是，免疫者。

We now have a strong starting point for searching three-digit numbers:

我们现在有了一个强有力的起点 用于搜索三位数字：

any 2 consecutive digits must be on the list of the two-digit immune.

任何 2 个连续的数字必须是 在二位数的免疫名单。

Those all end in 3 and 7,

这些都以3和7结尾，

so the only possibilities are these 8 options:

所以唯一的可能 是这8个选项：

the two-digit immune with additional 3s or 7s on their ends.

两位数免疫者与额外 3s 或 7s 在他们的末端。

3 can’t follow 3, nor 7 follow 7.

3 不能跟 3, 7 也不跟随 7。

And once again, adding the digits reveals that 237 and 537

再一次，添加数字 揭示了 237 和 537

are divisible by 3.

能被 3 整除。

737 is 67 times 11, so that leaves just 373,

737 是 67 乘以 11， 所以只剩下373，

which is, in fact, prime, and therefore immune.

是质数，因此是免疫者。

Could a four-digit number be immune?

一个四位数的数字 可以是免疫者吗？

No, any consecutive three digits would have to be immune,

不，任何连续的三位数字 必须是免疫者，

and there’s no immune three digit number that starts with a 7.

并且没有免疫的三位数 是以 7 开头的。

You rush out, but reach each home too late,

你冲出去， 但到达每个家都太晚了，

until the only immune left is 373.

直到唯一剩下的免疫者是 373。

You’re in the nick of time to scare off her would-be kidnapper;

你正处于吓唬她的 潜在绑架者的关键时刻；

not the vampire itself but a minion.

不是吸血鬼本身，而是一个奴才。

373 explains that she and the other immune are the subjects of an ancient prophecy

373 解释说她和其他免疫者 是一个古老预言的主题

that designated them as vampire slayers.

将他们指定为吸血鬼杀手。

They’d sometimes gather and try to figure out what a vampire is,

他们有时会聚在一起尝试 弄清楚吸血鬼是什么，

but no one had the slightest idea.

但没有人有丝毫的想法。

They found the idea of slaying things quite distasteful.

他们觉得杀人相当令人反感。

You both trail her would-be kidnapper back to a foreboding castle.

你们两跟踪她的潜在绑架者 回到一座不祥的城堡。

There you release the other kidnapped numbers

在那里你释放另一个被绑架的号码

and confront the vampire himself.

并亲自面对吸血鬼。

He’s powerless before the slayers, but ever the pacifists,

他在杀戮者面前无能为力， 但永远是和平主义者，

they round him up, return the lifeforce to his victims, and send him packing.

他们围捕他，归还生命力 给他的受害者，然后让他打包走人。

Numberland is safe... for now.

Numberland 现在是安全的 ……暂时。